2. April and May play with their roller skates at the town oval. From the cente skates 4 meters east and then 5 meters south. May skates 5 meters wes -ight turn of 70° and skates 4 meters. Who is farther from the center of the oval?
Answer:
To solve this problem, we need to find the distance of each skater from the center of the oval and compare them. Let’s assume that the center of the oval is point O.
April’s position can be represented as point A, which is 4 meters east and 5 meters south from point O. We can use the Pythagorean theorem to find the distance of A from O:
OA = √(4²+5²) = √(16+25) = √41 ≈ 6.4 meters
May’s position can be represented as point M, which is 5 meters west of point O. Then she turns 70° to the right and skates 4 meters. We can use trigonometry to find the distance of M from O. Let the angle between OM and the vertical be x:
sin(x) = 5/OM
OM = 5/sin(x)
After turning 70° to the right, the angle between OM and the vertical is 70°+90° = 160°. Therefore:
sin(160°) = 5/OM
OM = 5/sin(160°) ≈ 5.21 meters
Then May skated 4 meters further, so her final position is N, where NM = 4 meters. Using the Pythagorean theorem again, we can find the distance of N from O:
ON = √(OM²+NM²) ≈ 7.2 meters
Therefore, May is farther from the center of the oval than April.
tcpa whilst entails
Garden east kio ang mo town venue parks nature stage outdoor nparks sg park gardens book venues amk. Town garden overview. The gardens at town center
Town garden overview. Gardens town center. Ang mo kio town garden east
chepstow rogers 21st ruth
Town garden archives. Ang mo kio town garden east. East town garden kio ang mo park rocks egg amk embedded throughout neighbourhood scattered shaped these
bowleswyer
City garden in south west london – bowles & wyer. Westfield booragoon. Flat for sale hira residency in jamshed town garden east brand new
