4. Two cars leave an intersection at the same time, one traveling north and the other traveling east. Some time later, they are 20 miles apart, and the car going east has traveled 4 miles farther than the other car. How far has each car traveled?with equation po

Question

4. Two cars leave an intersection at the same time, one traveling north and the other traveling east. Some time later, they are 20 miles apart, and the car going east has traveled 4 miles farther than the other car. How far has each car traveled?with equation po​

neckhugger6 · Answer

Set point O as an intersection.First car travel north and the 2nd one travel east, now imagine they are going to make a right triangle. Triangle has 3 sides, named, a, b and c.c is the longest, a and b are the other both sides.Solution:Let the distance travel by the car going to the north equal to x and the car going to east travel 4+x. then,Use Pythagorean Theoremc² = a² + b²a = 4 + xb = xc = 2020² = (x + 4)² + x²400 = (x² + 8x + 16) + x²2x² + 8x - 384 = 0x² + 4x - 192 = 0(x + 16)(x - 12) = 0Solve for x:x + 16 = 0x = -16 ❌&&x - 12 = 0x = 12 ✅Now it explains that we cannot have a negative distance therefore we only conclude x = 12. The car traveling to north traveled 12 miles and the car traveling through east reach 4 + x = 4 + 12 = 16 miles.Answer:Car traveling North in a distance of 12 miles.Car traveling East in a distance of 16 miles.#CarryOnLearning

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