A man wants to plants a rectangular garden along one side of his house with a picket fence on the otthree sides of the garden find the dimensions of the largest garden that can be enclosed by using 48 m of fencing
Answer:
the largest rectangle is always a square
40/4=10 feet on each side
one side is not needed because of the house
add the 10 feet not needed to the opposite side to get a side 20 feet long
the rectangle is 10 by 20 by 10 and the house
A=lw
A=20*10
A=200 square feet
notice the 10 by 20 rectangle is made up of two 10 by 10 squares
Step-by-step explanation:
Tnx for asking (◕ᴥ◕)
