A. EVALUATE Determine The Experimental Probability: 1. Rock, Paper, Scissors 2. In 31 T…

A. EVALUATE Determine the experimental probability: 1. Rock, Paper, Scissors 2. In 31 tries, Eli beat Janine 11 times. What is the probability that Janine won? In 60 tries, May won 20 times. What is the probability that May won? In 40 tries, Ryan won over Ghie 10 times. What is the probability that Ghie won Tossing two dico a. b. C.​

A.

1. Rock, Paper, Scissors: The experimental probability of winning Rock, Paper, Scissors is 1/3 or approximately 0.333. This is because there are three equally likely outcomes (rock, paper, or scissors), and each has an equal chance of being chosen.

2. In 31 tries, Eli beat Janine 11 times. The probability that Janine won is (31 – 11) / 31 or 20/31. This is because there are 31 total tries, and Janine won the remaining 20 times.

3. In 60 tries, May won 20 times. The probability that May won is 20/60 or 1/3. This is because there are 60 total tries, and May won 20 of them.

4. In 40 tries, Ryan won over Ghie 10 times. The probability that Ghie won is (40 – 10) / 40 or 3/4. This is because there are 40 total tries, and Ghie won the remaining 30 times.

B. Tossing two dice:

a. The probability of rolling a sum of 7 when tossing two dice is 6/36 or 1/6. This is because there are six ways to roll a sum of 7 (1+6, 2+5, 3+4, 4+3, 5+2, 6+1) out of a total of 36 possible outcomes (6 sides on each die, for a total of 6×6=36 possible outcomes).

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b. The probability of rolling a sum of 2 or 12 when tossing two dice is 1/36. This is because there is only one way to roll a sum of 2 (1+1) or 12 (6+6) out of a total of 36 possible outcomes.

c. The probability of rolling a sum of 5 or 9 when tossing two dice is 4/36 or 1/9. This is because there are four ways to roll a sum of 5 (1+4, 2+3, 3+2, 4+1) or 9 (3+6, 4+5, 5+4, 6+3) out of a total of 36 possible outcomes.