A. Write the equation 15 - 4k = -3k2in standard form.

Question

A. Write the equation 15 - 4k = -3k2in standard form.​

Chyred236 · Answer

✏️Equation============================A. Write the equation 15 - 4k = -3k2in standard form.→Rearrange terms[tex]\purple{\boxed{	t15 - 4k =  - 3k²}}[/tex][tex]\purple{\boxed{	t - 4k + 15 =  - 3k²}}[/tex]→Move terms to the left side[tex]	t \: 4k + 15 =  - 3k²[/tex][tex]	t4k + 15 -  - 3k² = 0[/tex]→Rearrange terms[tex]	t4k + 15 -  - 3k² = 0[/tex][tex]\green{\boxed{	t3k² - 4k + 15 = 0}}[/tex]→Use the quadratic formula[tex]	t \: k = \green{\boxed{	t \frac{ - b +  \sqrt{b² - 4ac} }{2a} }}[/tex]Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.[tex]\green{\boxed{	t3k² - 4k + 15 = 0}}[/tex][tex]ed{\boxed{	t \: a = 3}}[/tex][tex]ed{\boxed{	t \: b =  - 4}}[/tex][tex]\blue{\boxed{\ \: c = 15}}[/tex][tex]	t \: k = \blue{\boxed{	t  \frac{ - ( - 4) +  \sqrt{( - 4)² - 4.3.15} }{2.3} }}[/tex]→SimplifyEvaluate the exponentMultiply the numbersSubtract the numbersMultiply the numbers[tex]	t \: k =  \frac{4 +  \sqrt{ - 164} }{6} [/tex]→No real solutions because the discriminant is negativeThe square root of a negative number is not a real number[tex]\green{\boxed{	t \: d =  -164}}[/tex]===============================#CarryOnLearning(ノ^_^)ノ

Coach Carvalhal

A. Write The Equation 15 – 4k = -3k2in Standard Form.

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Math Grade 7. 500+315

Write It In Standard Form (2k+6-7k³)+(8k³+3+9k⅝)

Divisible By 2 420. 332. 531. 517. 916. 123. 724. 508. 195

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