Factor the perfect square trinomial
8k²-8k+2
With Solution
Answer:
2(2k – 1)²
GCF = 2
Solution:
[tex]2 ( \frac{8k {}^{2} }{2} + \frac{8k}{2} + \frac{2}{2} ) \\ 2(4k {}^{2} – 4k + 1) \\ 2(2k) {}^{2} – 2(2k)(1) + 1 {}^{2} ) \\ 2(2k – 1) {}^{2} [/tex]
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