find the sum of all whole numbers n such that when 60 is divided by n it gives a remainder of 4
a. 120
b. 113
c. 57
d. 56
answer:
d. 56
explanation:
To solve this problem, we need to find all the factors of 60 that leave a remainder of 4 when divided into 60.
First, we can list out the factors of 60:
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Then, we can divide 60 by each of these factors and see which ones leave a remainder of 4:
60 ÷ 5 = 12 remainder 0
60 ÷ 10 = 6 remainder 0
60 ÷ 15 = 4 remainder 0
60 ÷ 20 = 3 remainder 4
60 ÷ 30 = 2 remainder 0
Therefore, the only factors that leave a remainder of 4 are 20 and 40.
The sum of these two factors is:
20 + 40 = 60
So the answer is d. 56 is not a valid answer since it is not the sum of any factors of 60.
