I went for a walk the other day.I went four avenues East (0.80miles),then twenty four street South (1.20miles),the one avenues West (0.20miles),and finally eight streets North(0.40miles)
1. The distance = 2.6 miles
2. The direction of displacement : 53.06 ° relative to due east
Further explanation
Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude
Can be simplified distance = totals traveled
Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction
Can be simplified displacement = distanced traveled from starting point to ending point
He went four avenues east (0.80 miles), then twenty-four streets south (1.20 miles), then one avenue west (0.20 miles), and finally eight streets north (0.40 miles).
1. The distance = total miles traveled
The distance = 0.8 + 1.2 + 0.2 + 0.4 = 2.6 miles
2. resultant displacement (magnitude and direction relative to due east)
To find the magnitude of the displacement we use the phytagorean formula (attachment)
The adjacent: the horizontal distance = 0.8 east-0.2 west = 0.6 miles
The opposite side: the vertical distance = 1.2 south – 0.4 north = 0.8 miles
The displacement = D :
[tex]\rm D=\sqrt{0.6^2+0.8^2}=1~miles[/tex]
The direction of displacement is calculated using tangent
Tan θ = Opposite ÷ Adjacent.
[tex]\rm Tan~\theta=\dfrac{0.8}{0.6}=1.33\\\\\theta=53.06^o~relative~to~due~east[/tex]
Further explanation
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