what chemical reaction is 3I2+6KOH==5KI+KIO+3H2O
Answer:
3 I2 (s) + 6 KOH (aq) → KIO3 (aq) + 5 KI (aq) + 3 H2O (l)
This is an oxidation-reduction (redox) reaction:
5 I0 + 5 e- → 5 I-I
(reduction)
I0 – 5 e- → IV
(oxidation)
I2 is both an oxidizing and a reducing agent (disproportionation (dismutation)).
